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Posted by Jerry M. Gartner on 06/26/06 06:18
That did the trick thanks much for the input.
--
Regards,
Jerry M. Gartner
"Jerry Stuckle" <jstucklex@attglobal.net> wrote in message
news:d4ednVp2qf62MQHZnZ2dnUVZ_tidnZ2d@comcast.com...
> Jerry M. Gartner wrote:
>> Greetings:
>>
>> As evident from a previous post, I am a php noob. I would like to
>> display MySQL query results in an html table with one of the row values
>> as a category and the rest of the data displayed under the relevant
>> category.
>>
>> I can get as far as displaying the data in a nice readable format but
>> I don't know how to have the records placed under their corresponding
>> category. This is my code thus far (sans the html output):
>>
>> ...ORDER BY cat ASC';
>> while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
>> printf("%s Class: %s Description: %s", $row["cat"]$row["title"],
>> $row["desc"]);
>> }
>>
>> As you can see, this only outputs each record with the selected rows
>> but we show multiple instances of the same category. I know why this
>> works the way it does, I just don't know how to make it work the way I
>> want. Advice is appreciated. Thanks in advance.
>>
>> Also, any good links for understanding and using arrays are welcome.
>
> Something like:
>
> $cat = ""; // Or any value you would never have for a category
> while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
> if ($row['cat'] != $cat) {
> echo $row['cat'] . ' ';
> $cat = $row['cat'];
> }
> echo 'Class: ' . $row['title'] . "Description" . $row['desc'];
> }
>
> --
> ==================
> Remove the "x" from my email address
> Jerry Stuckle
> JDS Computer Training Corp.
> jstucklex@attglobal.net
> ==================
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