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Posted by J.O. Aho on 10/11/67 11:52
Jarrod wrote:
> Hi there,
>
> I am trying to get the value of the varible into an if statment that will
> determine what to do.
>
> The value is from the end of an array, this works fine when i use echo to
> print it out onto the page but cant pass the value into the if statement,
> can someone please help me
>
> $testing = '10';
> $end = end($array); // this would equal to 10
in this example, the array is empty, so you need to assign a value to the array.
>
> if($testing == $end){
> print 'yes';
> }else{
> print 'no';
> }
>
Try this one instead
$testing = '10';
$array = array(1,2,3,10);
$end = end($array); // this would equal to 10
if($testing == $end){
print 'yes\n';
}else{
print 'no\n';
}
If you want to give up end(), you can use:
$testing = '10';
$array = array(1,2,3,10);
$end = $array[count($array)-1];
if($testing == $end){
print 'yes\n';
}else{
print 'no\n';
}
If I would be you, I would try to keep integers as integers and not as
strings, so I would have used '$testing = 10;' instead of what you have.
//Aho
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