You are here: Converting argv to variable « PHP Programming Language « IT news, forums, messages
Converting argv to variable

Posted by tgiles on 12/17/87 11:53

I've taken a year off (or so) using Python and the first thing I run
into utterly stumped me. Been too long and none of the searches I've
done seems to have helped any.

Basically, I'm trying to create a little script which will make a new
directory, using the argument passed to it to give the directory a
name:

#!/usr/bin/python

import sys, os

newDirectory = str(sys.argv[1:])

currentPath = str(os.getcwd())

create = currentPath + '/' + newDirectory

print create

# os.mkdir(create)

Now, in a perfect universe I would get an output something like the
following (if I run the script with the argument 'python':

/Volumes/Home/myuser/python

However, Python still hangs on to all the fluff and prints out
something else:

/Volumes/Home/myuser/['python']

I know there must be some way to convert the argument to a 'normal'
variable, but it escapes me how to do so. Any pointers?

Thanks!

tom

 

Navigation:

[Reply to this message]


Удаленная работа для программистов  •  Как заработать на Google AdSense  •  England, UK  •  статьи на английском  •  PHP MySQL CMS Apache Oscommerce  •  Online Business Knowledge Base  •  DVD MP3 AVI MP4 players codecs conversion help
Home  •  Search  •  Site Map  •  Set as Homepage  •  Add to Favourites

Copyright © 2005-2006 Powered by Custom PHP Programming

Сайт изготовлен в Студии Валентина Петручека
изготовление и поддержка веб-сайтов, разработка программного обеспечения, поисковая оптимизация