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Posted by Chuck Anderson on 06/09/05 04:06
I have a function with 7 inputs. The last three have default values.
I want to call that function specifying the first four, skip two and
then specify the last.
I thought I could write this as :
$retval = myfunction(arg1, arg2, arg3, arg4,,,arg7);
.... but Php does not seem to want to let me do this. I get a parse
error until I supply values for the 5th and 6th arguments.
My question is simply this; is skipping arguments like that not allowed
in Php?
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Chuck Anderson • Boulder, CO
http://www.CycleTourist.com
Integrity is obvious.
The lack of it is common.
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