Posted by rich on 12/16/22 11:58

I keep getting the error:
Warning: in_array(): Wrong datatype for second argument on line 679
here is the code.
I declare and fill the array
$specprimA = array();
$specprimA= getspecprim($dresstypeid);
$primsecA=getprimsec();

Then I do a compare using in Array. I even put in the extra step of
making sure I have something in the array with the is sizeof statement.

$numcl= count($primsecA);
for ($i=0; $i<$numcl; $i++){
$primsec = $primsecA[$i]['primsec'];
if (sizeof($specprimA) >0){
if (in_array($primsecA[$i]['primsecid'], $specprimA)) { ?>
<input type="checkbox" checked tabindex="2" name="primsecid[]"
value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
$primsec;
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
}?>

This is line 679
if (in_array($primsecA[$i]['primsecid'], $specprimA)) { ?>

Any ideas why?

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