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Posted by Garry Jones on 10/05/06 20:06
<halkeye@gmail.com> skrev i meddelandet
news:1160075930.560400.315630@e3g2000cwe.googlegroups.com...
> Off the top of my head, since you don't say what $dtctxsz1 is. I'd say
> its because $dtctxsz1 is blank or null, which "== 0" returns true for.
Here is some more of the offending code.
First - Exerpt from a form.
<select name="dtctxsz1" class="vtredstar" id="dtctxsz1">
<option value="0" selected>Ej vald</option>
<option value="xs">XS</option>
<option value="s">S</option>
<option value="m">M</option>
<option value="l" >L</option>
<option value="xl">XL</option>
<option value="xxl">XXL</option>
<option value="xxxl">XXXL</option>
</select>
Processed by.....
$antroj = 0;
$dtctxsz1 = $_POST["dtctxsz1"];
if($dtctxsz1 == 0){
print $dtctxsz1;
$antroj = $antroj + 1;
}
If the user chooses xl the value of $dtctxsz1 is xl.
It should not then execute the print command because $dtctxsz1 is not 0.
However it prints, and it prints the value the user clicked on - in this
case xl
It should not be adding one to the value of $antroj should it. But it is!
If the value was misfiring it would be printing 0 because it can only print
when the value is 0. So I am missing something here!
Greatful for any help in this matter.
Garry Jones
Sweden
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