fopen is function that open files.
see this: http://php.net/manual/en/function.fopen.php
Bob Bedford написа:
> Hi all,
>
> I'm trying to pass a fopen() ressource result as a parameter.
>
> $x=fopen($filename);
> header('location:myfile.php?ressource='.$x);
>
> but it doesn't seem to work.
>
> How to do so ?
>
> Bob