Posted by frizzle on 10/12/06 14:44

Hi there,

I'm not really experienced with regexpes etc. so that's why i come
here.
My script needs to parse the requested filename:

Imagine the filename is index_en.html
My output needs to be an array with the following:
language => en (no underscore)
file => index (no "_en")
extension => html

i created the following, but i don't know how to move on:
preg_split( '/^[a-z0-9]*(_(en|_ru))?\.[a-z0-9]{2,4}$/', $filename );

As you can see, the _en part can be left out (index.html) wich would
have to return
language => default

I hope it's clear, cause i really need to get this going!

Thanks.

Frizzle.

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