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Posted by Robert Cummings on 02/01/05 03:50
On Mon, 2005-01-31 at 20:41, Pagongski wrote:
> I have this function:
>
> function supscript($texto)
> {
> print("<sup>".$texto."</sup>");
> }
>
> But when i do:
>
> print "2".supscript("3");
>
> I get the "3" before the "2", how is that posible?
>
> And:
>
> print(supscript("3")."2");
>
> makes the 2 appear before the 3.
> I am confused!
Your second example does not print the 2 before the 3. And the reason
your first example prints the 3 before the 2 is because the the print
inside the function prints first because the print that contains the
call to it can't print until it receives the return value form the
function. What you probably want is the following:
function supscript($texto)
{
return "<sup>".$texto."</sup>";
}
print "2".supscript("3");
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