Posted by Jerry Stuckle on 02/03/07 05:08

PI wrote:
> Hi guys, I need some urgent help here please:
> I am using an include_once() command to include a file that sits a
> level above the file view.php. when the code is run, I have an error
> as follows:
>
> Warning: include_once(../common.php) [function.include-once]: failed
> to open stream: No such file or directory in C:\Program Files\..
> \view.php on line 2
>
> Warning: include_once() [function.include]: Failed opening '../
> common.php' for inclusion (include_path='.;C:\Program Files\xampp\php
> \pear\') in C:\Program Files\...\view.php on line 2
>
> The include command is simply: include_once(../common.php) - the '../'
> before the 'common.php' to indicate a level above the current file
> level. Is this right? I could not find a resource to confirm this.
>
> The strange thing is that while the error seems to imply that the
> calling file, view.php cannot 'see' the common.php file, other
> functions called from the 'common.php' file executes correctly and on
> the same calling file/page (view.php).
>
> Appears to the a double take - quite confusing - a PHP newbie and I'd
> appreciate your prompt response, thanks
>

Among other things - since it's a string, you need quote marks around
the filename - i.e.

include_once('../common.php'); // double quotes also work

Is this a web page or a cli program?

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================

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