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Re: Passing variables out of a function

Posted by Akhenaten on 05/18/07 14:47

On May 18, 9:18 am, Akhenaten <jonko...@gmail.com> wrote:
> For whatever reason I can't get my return value to pass outside of the
> function I've created. I've tested all the responses within the
> function so I know the data is there and the sql query is valid. Am I
> missing something to get it passed outside the function?
>
> ******************************
>
> function respond_check($qid,$username)
> {
> include "db.inc.php";
> $postchk2 = mysql_query("SELECT username FROM `answers` , `users`
> WHERE `qid` = $qid AND `a_uid` = `userid` LIMIT 0, 30",$db);
> while ($userx=mysql_fetch_array($postchk2))
> {
> if (in_array($username,$userx)) {
> $freturn = 7;
> return $freturn;
>
> }
> }
> }
>
> ******************************

Disregard -- it's always the simple mistakes that make you pound your
head. I failed to make $freturn global.

 

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