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Posted by Marcel on 07/08/05 10:45
"Markus L." <nobody@project-sca.org> schreef in bericht
news:pan.2005.07.07.21.25.10.949260@project-sca.org...
> Am Thu, 07 Jul 2005 22:59:56 +0200 schrieb Marcel:
>
>> Hello all,
>>
>> I am looking for a perfect PHP age calculator which takes someones date
>> of
>> birth as an argument and returns the person's age.
>>
>> I went over several tutorials, help and newsgroups an found lots of
>> calculators, tried many times to make the perfect script but did not
>> find/make the perfect one.
>>
>> Simple test:
>>
>> if my birthdate is 07-07-2004 (dd-mm-yyyy) and today is 07-07-2005 then i
>> should be 1 year old
>>
>> if my birthdate is 07-07-2004 (dd-mm-yyyy) and today is 06-07-2005 then i
>> should be 0 years old
>>
>> Lots of scripts i've found did not pass this test succesfull, so if
>> someone
>> can point me to the 'golden' script then i would be very thankfull!
>>
>> Regards,
>>
>> Marcel
>
> The script is written in 2 minutes:
> <?php
> $birthday = '07-07-2004';
> $today = date('d-m-Y');
>
> $a_birthday = explode('-', $birthday);
> $a_today = explode('-', $today);
>
> $day_birthday = $a_birthday[0];
> $month_birthday = $a_birthday[1];
> $year_birthday = $a_birthday[2];
> $day_today = $a_today[0];
> $month_today = $a_today[1];
> $year_today = $a_today[2];
>
> $age = $year_today - $year_birthday;
>
> if (($month_today < $month_birthday) || ($month_today == $month_birthday
> && $day_today < $day_birthday))
> {
> $age--;
> }
> ?>
>
> --
Thank you!!!
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