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Posted by M A Srinivas on 07/30/07 09:13
On Jul 27, 1:28 am, mcolson <mcolson1...@gmail.com> wrote:
> On Jul 26, 2:43 pm, mcolson <mcolson1...@gmail.com> wrote:
>
>
>
>
>
> > On Jul 26, 2:21 pm, Jason Lepack <jlep...@gmail.com> wrote:
>
> > > select
> > > sum(box)
> > > from (
> > > select top 2
> > > box
> > > from
> > > your_table
> > > order by
> > > id desc)
>
> > > Cheers,
> > > Jason Lepack
>
> > > On Jul 26, 3:16 pm, mcolson <mcolson1...@gmail.com> wrote:
>
> > > > I am trying to create a stored procedure that will add the last two
> > > > entries from a column. If I had a column named box, I would want to
> > > > add the two values in box, for which my ID column is Max and Max-1.
>
> > > > Is there anyone who can help me with this?
>
> > > > Matt
>
> > so i should
> > SET box = select
> > sum(box)
> > from (
> > select top 2
> > box
> > from
> > batchdaa
> > order by
> > IDnum desc)
> > ?
>
> ahh the power of parenthesis
>
> box = (SELECT SUM(box) FROM batchdata WHERE IDnum >= (SELECT
> (MAX(IDnum)-1) FROM batchdata))
>
> I had to make sure the parenthesis were all in the correct spot.
> Especially since I am doing this for 4 columns and there was a comma
> at the end- Hide quoted text -
>
> - Show quoted text -
You need to make sure the following . (assuming you don't want to sum
duplicate values )
1. There are no duplicate maximum values
2. A row with maximum - 1 exists and this also should not have any
duplicates .
you may be looking for next to maximum ( not max - 1 ) . ie
Your values should not have gaps
8
6
5
3
In this case max = 8 , max - 1 = 7 does not exist
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