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Posted by Reggie on 09/04/07 19:19
Am getting this notice.any ideas:
Notice: Undefined index: completed in /home/fhlinux169/c/
clashoff.co.uk/user/htdocs/picture.php on line 17
Notice: Undefined index: gim in /home/fhlinux169/c/clashoff.co.uk/user/
htdocs/picture.php on line 52
This is the script :
<?php
// Connect to database
$errmsg = "";
if (! @mysql_connect("","","")) {
$errmsg = "Cannot connect to database";
}
@mysql_select_db("");
// First run ONLY - need to create table by uncommenting this
// Or with silent @ we can let it fail every sunsequent time ;-)
// Insert any new image into database
if ($_REQUEST['completed'] == 1) {
// Need to add - check for large upload. Otherwise the code
// will just duplicate old file ;-)
// ALSO - note that latest.img must be public write and in a
// live appliaction should be in another (safe!) directory.
move_uploaded_file($_FILES['imagefile']
['tmp_name'],"latest.img");
$instr = fopen("latest.img","rb");
$image = addslashes(fread($instr,filesize("latest.img")));
if (strlen($instr) < 149000) {
mysql_query ("insert into pix (title, imgdata) values
(\"".
$_REQUEST['whatsit'].
"\", \"".
$image.
"\")");
} else {
$errmsg = "Too large!";
}
}
// Find out about latest image
$gotten = @mysql_query("select * from pix order by pid desc limit 1");
if ($row = @mysql_fetch_assoc($gotten)) {
$title = htmlspecialchars($row['title']);
$bytes = $row['imgdata'];
} else {
$errmsg = "There is no image in the database yet";
$title = "no database image available";
// Put up a picture of our training centre
$instr = fopen("../wellimg/ctco.jpg","rb");
$bytes = fread($instr,filesize("../wellimg/ctco.jpg"));
}
// If this is the image request, send out the image
if ($_REQUEST['gim'] == 1) {
header("Content-type: image/jpeg");
print $bytes;
exit ();
}
?>
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