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Posted by J. Frank Parnell on 09/07/07 18:22
On Fri, 07 Sep 2007 18:47:47 +0200, "Rik Wasmus" <luiheidsgoeroe@hotmail.com>
wrote:
>On Fri, 07 Sep 2007 17:57:00 +0200, J. Frank Parnell <pos@edgecity.ufo>
>wrote:
>
>> On Fri, 07 Sep 2007 07:22:46 -0400, Jerry Stuckle
>> <jstucklex@attglobal.net>
>> wrote:
>>
>>> J. Frank Parnell wrote:
>>>> On Thu, 06 Sep 2007 21:41:27 -0400, Jerry Stuckle
>>>> <jstucklex@attglobal.net>
>>>> wrote:
>>>>
>>>>> J. Frank Parnell wrote:
>>>>>> Hello,
>>>>>> So, I was wondering how to do this:
>>>>>>
>>>>>> foreach($foo as $k=>$v AND $bar as $k2=>$v2){
>>>>>> echo '<TR><TD>$k</TD><TD>$v</TD><TD>$k2</TD><TD>$v2</TD></TR>;
>>>>>> }
>>>>>>
>>>>>> Thanks,
>>>>> No.
>>>>>
>>>>> However, you can use "each" to do the same thing, i.e.
>>>>>
>>>>> reset $array1;
>>>>> reset $array2;
>>>>>
>>>>> for ((list($key1, $val1) = each($array1)) &&
>>>>> (list($key2, $val2) = each($array2)) {
>>>>> // $key1 and val1 contain the key and value for an element in $array1
>>>>> // $key2 and val2 contain the key and value for an element in $array2
>>>>> // Do your stuff here
>>>>> }
>>>>>
>>>>> It will stop as soon as you run out of elements in either array.
>>>>
>>>> Ah, cool, I saw similar on the php.net. Is there a way to do it so
>>>> that it will
>>>> go thru all of both, even if one runs out?
>>>>
>>>
>>> What do you want to do with the array which runs out? And what do you
>>> want to do with the array with items left?
>>
>> I figured the var that ran out would just be empty while the other var
>> is still
>> listing, eaching, etc. It might be handy to be able to specify a
>> default value
>> instead of empty, like   for the table exapmle above. Looks like I
>> could
>> just stick a little if() in Satya's code.
>
>Or an array_pad() on the smaller one...
Well, neither of these are working, Jerry's (both scripts) have a syntax error,
(missing ; and I cant figure where it wants it) and Satya's outputs:
0 Array 0 0
1 Array 1 1
2 Array 2 2
3 Array 3 3
4 4
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