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Re: binary and & vs &=

Posted by Steve on 11/09/07 18:49

"Darko" <darko.maksimovic@gmail.com> wrote in message
news:1194632959.294732.216730@k79g2000hse.googlegroups.com...
> On Nov 9, 7:11 pm, "Steve" <no....@example.com> wrote:
>> "Darko" <darko.maksimo...@gmail.com> wrote in message
>>
>> news:1194624540.774587.257620@o3g2000hsb.googlegroups.com...
>>
>> > On Nov 9, 3:35 pm, joshuajnoble <joshuajno...@gmail.com> wrote:
>> >> Is there any difference between doing:
>>
>> >> $var & 0x80;
>>
>> >> and
>>
>> >> $var &= 0x80;
>>
>> >> I've seen the second, using the &= in production code, but on my local
>> >> machine it errors out. Any thoughts?
>>
>> > $var &= 0x80 <=> $var = $var & 0x80
>>
>> perhaps <=> is a non-standard equality to the op. you mean that both
>> accomplish the same thing...they are just two different ways of writing
>> the
>> same thing, right?
>
> In math, <=> means "is equivalent to".

right. however, i was considering the question posed by the op...dealing
with hex and bits. he's probably not going to immediately see that you're
saying they're equal.

no big.

 

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