|
Posted by The Natural Philosopher on 11/14/07 15:53
Lloyd Harold wrote:
> The Natural Philosopher <a@b.c> wrote:
>
>> $query="select * from mytable where location ='4'";
>> $result=mysql_query($query);
>>> Each result should be displayed in it's own paragraph.
>>>
>> if ($result && ($rows=myql_numrows($result) >0))
>> {
>>> Each result should be within a link to open a new page (details.php ?)
>>> that will retrieve the details for that name.
>>>
>> for($i=0;$;<$rows;$i++)
>> {
>>> Ideally, but not essentially, the new page should contain a link back to
>>> the previous results.
>>>
>> $last_id=$__GET['id'];
>> $var1=mysql_result($result,'id); // and any other variables you
>> want.
>> printf("<p><A HREF=Mycode.php?id=%d>id=%d,</A>\r\n",
>> $last_id,$var1);
>> }
>> }
>
> Thanks for your prompt response.
>
> I've tried the code and am seeing this error:
>
> PHP Parse error: parse error, expecting `T_VARIABLE' or `'$'' in /- on
> line 25, which is:
>
> for($i=0;$;<$rows;$i++)
theres missing i in there. Sorry. I don't debug the typos for free ;-)
Navigation:
[Reply to this message]
|