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Posted by Steve on 11/20/07 16:04
"VooDoo" <VooDooNet38@free.fr> wrote in message
news:fhuulb$72s$1@reader1.imaginet.fr...
> Hi,
> I am getting confused with sorting arrays...
> $arraytest =array(5) { [0]=> string(2) "39" [1]=> string(2) "44" [2]=>
> string(2) "77" [3]=> string(3) "150" [4]=> string(3) "464" }
>
> why do i get NULL value if i try to sort this array using sort command?
>
> sort($arraytest);
poorly asked question.
sort() performs a sort on the $array parameter by reference. sort() does NOT
return the sorted version of $array as a result of its operation. so...
<?
$array = array(
'39' ,
'44' ,
'77' ,
'150' ,
'464'
);
sort($array);
echo '<pre>' . print_r($array, true) . '</pre>';
?>
will print the array and show that the values are sorted from lowest to
highest.
btw, leave out the array(5) string(2) [0]=> shit. it makes reading the code
a pain in the ass and isn't needed in the least...it doesn't make any impact
on the way php executes that code. if coded like the above, you can easily
see what *actual* values are making up the members of the array...rather
than trying to weed out the other junk surrounding them (like what index it
has or what data-type you are *casting* it to). the extra crap is feckless
and less than useful.
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