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 Posted by Frank Arensmeier on 02/24/05 11:46 
Thank you Stian! 
 
In Swedish they say "Sometimes you can't see the forest by all the  
trees." 
 
/frank 
 
2005-02-24 kl. 09.45 skrev Stian Berger: 
 
> On Thu, 24 Feb 2005 09:14:32 +0100, Frank Arensmeier  
> <frank.arensmeier@nikehydraulics.se> wrote: 
> 
>> Hello everybody! 
>> 
>> I was wondering if you could help me with a little problem I ran into  
>> some days ago. 
>> 
>> In my database I have some information about file paths. Originally,  
>> those paths come from a Windows Excel spreadsheet and look like "..\1  
>> PDF Filer\65051.PDF". In my PHP code I try to do two things: 
>> 
>> 1) replace ".." with a string like "file://server/folder" 
>> 2) replace all "\" characters with "/". 
>> 
>> The PHP code looks something like: 
>> 
>> $path_to_file = "..\1 PDF Filer\65051.PDF"; 
>> $things_to_look_for = array("..", "\"); 
>> $things_to_replace_with = array("file://server/folder", "/"); 
>> $link = str_replace($things_to_look_for, $things_to_replace_with,  
>> $path_to_file); 
>> 
>> The big problem is the character "\" which, if I got it right, in  
>> UNICODE is used for things like expressing line breaks ('\n' or  
>> something like this). The code above is resulting in the following  
>> error massage: "Parse error: parse error, expecting `')'' in  
>> /xxx/xxx/xxx/TMPz06yoces6o.php on line 2." 
>> 
>> Is there a simple solution for this problem? 
>> 
>> Regards, 
>> 
>> Frank 
> 
> 
> You are escaping the last quote, meaning that the rest of your code is  
> "quoted". What you need to do is to escape the escape character. 
> 
> $path_to_file = addslashes("..\1 PDF Filer\65051.PDF"); 
> $things_to_look_for = array("..", "\\"); 
> 
> You should use addslashes() or similar on you're path name, as some  
> escaped characters have certain meanings. \n for example means a new  
> line character, while \\n on the other hand means \ followed by n. 
> 
> Manual: http://www.php.net/types.string 
> 
> --  
> Stian 
> 
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> 
> 
> 
>
 
  
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