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Posted by Jochem Maas on 03/03/05 16:29
Jason Petersen wrote:
> On Wed, 2 Mar 2005 13:02:39 +0200, William Stokes <kalles@operamail.com> wrote:
>
>>Hello
>>
>>Can someone explain this to me. I don't know how to read this.
>>
>>if (!$variable = mysql_query("select id,sessid from users where ...
>>
>>What is this "if(!"
>
>
> This is a way to run a SQL query, capture the return value, and
> perform an action if the query failed. For code readability, I would
> probably write that as two statements:
>
> $variable = mysql_query("SELECT * FROM blah");
> if(!$variable) { error_handler(mysql_error()); }
in terms of readability an alternative if to write it like so:
if(! ($variable = mysql_query("SELECT * FROM blah")) {
// do stuff
}
what you have to realise is that the expression '$variable = mysql_query("SELECT * FROM blah")'
has a return value itself - which just happens to be the same as the value of $variable.
to put it another way, when you do:
echo $variable;
your not saying:
"output the contents of this variable"
but your actually saying:
"output the result of the expression '$variable'"
it just so happens that the result of the expression is this case
if the contents of $variable.
hopefully you get what I mean!, no doubt there are others that can explain it better!
>
> See the documentation for information on mysql_query return values:
> http://us2.php.net/manual/en/function.mysql-query.php
>
> Jason
>
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