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Re: Problem with table...

Posted by jukka on 01/08/06 00:13

Leszek wrote:
> I wrote a php script that reads some dara from database and displays it as
> a table:
> The problem is that the data are showing in table rows Is it possible to
> display it as a new colum next to an existing one?
>
>
> Here is php code::
>
>
> echo "<table align=\"center\" width=\"100%\">";
> echo"<tr><td>Room:</td></tr>";
> echo"<tr><td>Price:</td></tr>";
> echo"<tr><td>How many rooms?:</td></tr>";
>
> // data display
>
> $wynik2=mysql_query($hotel_query2);
> while($wiersz2=mysql_fetch_array($wynik2,MYSQL_NUM))
> {
> echo"<tr><td>".return_data($wiersz2[0])."</td></tr>";
> echo"<tr><td >".return_data($wiersz2[1])."</td></tr>";
> echo"<tr><td >".return_data($wiersz2[2])."</td></tr>";
> }
> echo "</table>";
>
> Each while pass creates 3 rows. Is it possible to make new column (with 3
> rows) next to the one that already exists?
>
> Thanks.
> Leszek
>
>
maybe:

echo "<table align=\"center\" width=\"100%\">";

// data display

$wynik2=mysql_query($hotel_query2);
while($wiersz2=mysql_fetch_array($wynik2,MYSQL_NUM))
{
echo "<tr><td>Room:</td><td>".return_data($wiersz2[0])."</td></tr>";
echo "<tr><td>Price:</td><td>".return_data($wiersz2[1])."</td></tr>";
echo "<tr><td>How many
rooms?:</td><td>".return_data($wiersz2[2])."</td></tr>";
}
echo "</table>";

 

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