Posted by Justin Koivisto on 01/11/06 16:08

Jaak wrote:
> I have this query, it gives the suspected information in myphpadmin:
>
> select listid, count(*) from table1 group by listid
>
> How do I put this the result into an array in php? I have problems with the
> count(*) field
>
>

$q='select listid, count(*) from table1 group by listid';
$res=mysql_query($q);
if($res){
$data=array();
while($row=mysql_fetch_array($res,MYSQL_NUM)){
$data[]=array(
'listid' => $row[0],
'count' => $row[1]
);
}
}

Untested, but it should give you the idea... Another option is to change
the query to something similar to:

select listid, count(*) as num_found from table1 group by listid

Then if you are using mysql_fetch_assoc, then the key name will be
'num_found'

HTH

--
Justin Koivisto, ZCE - justin@koivi.com
http://koivi.com

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