Posted by Jochem Maas on 10/01/08 11:12

HarryG wrote:
> Hi,
>
> I am connecting to two database in my index.php.
>
> Here is how:
> @ $db = mysql_connect("localhost", USERLOGIN, USERDBPASS);
> if (!$db)
> { print "Error: Could not connect to database. Please try again later."; exit; }
> mysql_select_db(DATABASE);
>
> @ $userdb = mysql_connect("localhost", USERLOGIN, USERDBPASS);
> if (!$userdb)
> { print "Error: Could not connect to database. Please try again later."; exit; }
> mysql_select_db(USERDB);
>
> $getaccount = "SELECT * FROM account WHERE visible=1"; //Account table is present in USERDB.
> $result = mysql_query($getaccount);
>
> $get = "SELECT * FROM useraccount"; //UserAccount table is present in DATABASE.
> $result = mysql_query($get);
>
> There is no problem with the connection. but I need to query tables in both databases. I know you need to use link identifiers,
> but have had no luck in getting it to work. Appreciate your help.

er, you are not actually using the link identifiers.... try like this:


@ $db = mysql_connect("localhost", USERLOGIN, USERDBPASS);
if (!$db) {
print "Error: Could not connect to database. Please try again later."; exit; }
mysql_select_db(DATABASE, $db);
}

@ $userdb = mysql_connect("localhost", USERLOGIN, USERDBPASS);
if (!$userdb) {
print "Error: Could not connect to database. Please try again later."; exit; }
mysql_select_db(USERDB, $userdb);
}

$getaccount = "SELECT * FROM account WHERE visible=1"; //Account table is present in USERDB.
$result = mysql_query($getaccount, $userdb);

$get = "SELECT * FROM useraccount"; //UserAccount table is present in DATABASE.
$result = mysql_query($get, $db);

>
> Thanks.
> HarryG
>

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