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Posted by Sugimoto on 04/20/05 10:15
Thank you very much, I do appreciate your help.
Ur script doens work, but, curiously, it works when I changed a bit...
select left(loc1,3) as locx, openart_id, tit1, pub1, id1, ref1 from
openart_table
If possible, can I ask one more thing?
This part is the problem
<A HREF="/momatlib/image/<? echo $row["locx"]; ?>.jpg"><? echo
$row["locx"]; ?></A>
I got 3 letters, but I would like to show all "loc1" data (eg "1-2 near
entrance") in the table, and have first 3 letters of "loc1" for jpg
hyperlink (http://www.heyjude.com/image/1-2.jpg).
Do you know how to fix this?
----script------------------
$result = mysql_query("select left(loc1,3) as locx, openart_id, tit1, pub1,
id1, ref1 from openart_table
where tit1 like '%$tit%'
and res1 like '%$res%'
and pub1 like '%$pub%'
and date1 like '%$date%'
and id1 like '%$id%'
and ref1 like '%$ref%'
and loc1 like '%$loc%'
and type1 like '%$type%'
and vol1 like '%$vol%'
and fre1 like '%$fre%'
and note1 like '%$note%' order by tit1");
$rows = mysql_num_rows($result);
echo $rows,"Record Found <p>";
while($row = mysql_fetch_array($result)){
?>
<tr>
<td><a href = "openart_detail.php ?iden=<? echo $row["openart_id"] ?>"><?
echo $row["openart_id"]; ?></a><br></td>
<td><? echo $row["tit1"]; ?><br></td>
<td><? echo $row["pub1"]; ?><br></td>
<td><? echo $row["id1"]; ?><br></td>
<td><? echo $row["ref1"]; ?><br></td>
<td>
<A HREF="/momatlib/image/<? echo $row["locx"]; ?>.jpg"><? echo
$row["locx"]; ?>
</A><br>
</td>
</tr>
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