|
|
Posted by Jason Barnett on 04/28/05 16:54
Vedanta Barooah wrote:
> btw! saying:
>
> add($a=null,$b=null,$c=null)
>
> is as good as saying:
>
> add($a,$b,$c)
>
No, it's not. Because in this case $a, $b and $c are all uninitialized
variables and (if this is a function definition) then you *have* to
supply $a $b and $c parameters.
Even if you were just calling add() this wouldn't be wise. Consider the
possibility that your server uses register_globals. In that case I can
browse to:
http://yoursite.com/yourpage.php?a=25&b=20&c=1234567890
Not to mention the code injection possibilities.
> thanks,
> vedanta
>
> On 4/28/05, Vedanta Barooah <vedanta.barooah@gmail.com> wrote:
>
>>Well that was simple, but this is what i am trying to solve:
>>
>>if you refer to the php documentation for ldap_open() function it says:
>>
>>resource ldap_search ( resource link_identifier, string base_dn,
>>string filter [, array attributes [, int attrsonly [, int sizelimit [,
>>int timelimit [, int deref]]]]])
>>
>>if you look at the 4th and the 6th arguments to the function
>>attributes is an array while sizelimit is an int, i want to pass the
>>sixth element without passing the 4th and the 5th ... how do i do
>>that??
>>
>>i tried these options:
>>
>># this does not work,
>>$rs=ldap_search($con,"o=vodoo.com","(objectClass*)",array(),0,500);
>>
$rs = ldap_search($con, "o=vodoo.com", "(objectClass*)", null, null, 500);
>># this wont works :((
>>$rs=ldap_search($con,"o=vodoo.com","(objectClass*)",' ',0,500);
>>
>># this also goofs!
>>$rs=ldap_search($con,"o=vodoo.com","(objectClass*)",NULL,0,500);
>>
>>here that 5th arg works if i pass a zero as ... 0 means the default behaviour!!
>>
>>any ideas ... clues ?
>>
>>Thanks,
>>Vedanta Barooah
>>
>>
Navigation:
[Reply to this message]
|