|  | Posted by Erland Sommarskog on 06/19/14 11:40 
mmt1 (mehrnaz.monajati@gmail.com) writes:> I have a multiplier that multiplies 2 floating point numbers with 7
 > bits exponent and 10 bits mantissa.so its output has 7 bits exponent
 > and 20 bits mantissa.
 > now its output must return to its input in order to compute another
 > multiplication.on the other hand its output must be truncated to 10
 > bits. how can I do this? please help me.
 
 This questions appears somewhat strange in the context of SQL Server.
 How is your data stored?
 
 In SQL Server there are two data types for floating-point values,
 real and float. real values have a 24-bit mantissa and 7-bit exponent
 and float have a 53-bit mantissa.
 
 Using these in the manner you ask for. If you have
 
 DECLARE @a real, @b real, @c real
 ...
 SELECT @a * @b * @c
 
 SQL Server first (probably) computes @a * @b which yields a new real
 number which then is multiplied with @c.
 
 --
 Erland Sommarskog, SQL Server MVP, esquel@sommarskog.se
 
 Books Online for SQL Server 2005 at
 http://www.microsoft.com/technet/prodtechnol/sql/2005/downloads/books.mspx
 Books Online for SQL Server 2000 at
 http://www.microsoft.com/sql/prodinfo/previousversions/books.mspx
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