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Posted by LJB on 02/12/06 08:33
I don't know if this was just a typo, but you have imgsrc run together
and you forgot to close the image tag with />. the code should read:
print '
<a href="http://www.somepage.com"><img src="someimage.jpg" /></a>';
break;
Denebola wrote:
> Now I am able to practice php on my pc, thanks to previous replies to a
>
> post in this forum, here the first of many questions.
>
> I want to be able to use an image as a link. So in html I would use:
>
>
> <a href="http://www.somepage.com">
> <img src="someimage.jpg">
> </a>
>
>
> I have written the php code below (which I am proud of !!):
>
>
> <?php
>
>
> // Switch statement based off server time
> switch (date('H i D'))
> {
> case '22 33 Sat':
> print '<img src="michelle.jpg" border="2" height="170"
> width="227" />';
> break;
>
>
> case '22 34 Sat':
> print '<img src="sunset.jpg" border="2" height="170"
> width="227" />';
> break;
>
>
> default:
> print 'Cases not met';
>
>
>
> }
>
>
> ?>
>
> Now the code above does what I want it to do but if I add the line
> below i get a parse error:
>
>
> case '22 35 Sat':
> print '<a
> href="http://www.somepage.com"><imgsrc="someimage.jpg"></a>';
> break;
>
>
> So how do I create a link from the images in my code?
>
>
> Regards
>
>
> p.s. please excuse the unintentional line breaks in the above code but
> they are not there in the actual code I have written.
>
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