Posted by Steve on 10/08/05 01:03

> $resultid = mysql_query ($query, $chan);
> if (!$resultid)
> die('Error getting position:' . mysql_error());

> $row = mysql_fetch_array($result);


You must have error reporting turned off. Your MySQL result is
$resultid, not $result.

---
Steve

• Next in forum: Re: I want to store multiple values in a single field
• Prev in forum: COUNT syntax
• Thread view: Re: COUNT syntax

[Reply to this message]