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Posted by iMi on 11/10/05 08:43
Just perfect Stefan! This is exactly what I've been looking for, even more,
this query retrieves has only the 'sections' which have a parent. Thanks a
lot !
---
iMi
"Stefan Rybacki" <stefan.rybacki@gmx.net> wrote in message
news:3te12oFs5b71U1@individual.net...
> iMi wrote:
>> Hello to all of you! I would appreciate if someone could help me out.
>> There are three tables in my database:
>>
>> --------------------------------
>> | table: sections |
>> --------------------------------
>> | section_id | parent_id |
>> --------------------------------
>> 1 0
>> 2 1
>>
>> -----------------------------------------------------
>> | table: section_descriptions |
>> -----------------------------------------------------
>> | section_id | language_id | section_name |
>> -----------------------------------------------------
>> 1 1 Home
>> 1 2 Caza
>> 2 1 News
>> 2 2 Notizie
>>
>> ------------------------------------------------------------
>> | table: languages |
>> ------------------------------------------------------------
>> | language_id | language_name | language_code |
>> ------------------------------------------------------------
>> 1 English en
>> 2 Italino it
>>
>> and I need a valid MySQL qury for output as shown below:
>>
>> --------------------------------------------------------
>> | section_id | section_name | section_parent |
>> --------------------------------------------------------
>> 2 News Home
>>
>> or
>>
>> --------------------------------------------------------
>> | section_id | section_name | section_parent |
>> --------------------------------------------------------
>> 2 Notizie Caza
>>
>>
>
> What did you try so far?
>
> Would this work for you, just a simple join of all the tables?
>
> SELECT a.section_id, b.section_name, d.section_name as section_parent FROM
> sections a JOIN
> sections c ON (a.parent_id=c.section_id) JOIN
> section_descriptions b ON (b.section_id=a.section_id) JOIN
> section_descriptions d ON (d.section_id=c.section_id) JOIN
> languages l ON (l.language_id=d.language_id AND
> b.language_id=l.language_id)
> WHERE l.language_code='en'
>
> Regards
> Stefan
>
>> Thanks in advance!
>> ---
>> iMi
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