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Posted by Lόpher Cypher on 01/02/06 08:18
cover wrote:
> So why is it that the following code returns data from a single table
> just fine? When 'all' is selected, all records are returned or if
> another selection is selected, only the ones specific to that group
> are returned for a single table. Code follows.
>
> $query =
> "SELECT *
> FROM $table
> WHERE 1 = 1 ";
> if($area != "All") $query .= "and area = '".$area."'";
> $result = mysql_query($query);
>
>
> ------------------------------------------------------------------------------------------------------------
> but where two tables have been successfully joined from a single form
> and data from the form is going into 2 separate tables I run into
> trouble on the query. The 'all' still returns everything as it
> should, pulling data from the two tables but individual selections
> used in a query form drop down that includes 'all' (i.e. to narrow to
> more specific areas), will not work any longer?
>
> $query =
> "SELECT shakers.area, shakers.equipname, shakers.equipno,
> shakers.coupler, motors.mccloc, motors.hp, motors.frame, motors.amps,
> motors.rpm, shakers.notes
> FROM shakers, motors
> WHERE shakers.equipno = motors.equipno ";
> if($area != "All") $query .= "and area = '".$area."'";
> $result = mysql_query($query);
>
> thanks again for any replies...
>
I think the problem might be that area is an ambiguous name in this
query (it is in both tables). Try changing it to
if ($area != "All") $query .= "and (shakers.area='$area' or
motors.area='$area')";
--
- lΓΌpher
---------------------------------------------
"Man sieht nur das, was man weiΓ" (Goethe)
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