Posted by David Dorward on 10/08/14 11:41
David Graham wrote:
> "The 50% 0 bit refers to the positioning of the background image
> I thought this would move the image over 50% from the left edge, resulting
> in no image being present down the left half of the screen.
No. It puts the point $x% along the image $x% along the horizontal length of
the container. So 100% would put the right hand edge of the image along the
right hand edge of the container. 10% would put the put 10% along the image
10% along the container. And so on.
--
David Dorward <http://blog.dorward.me.uk/> <http://dorward.me.uk/>
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