Posted by Oli Filth on 11/18/33 11:44

Jerry Stuckle said the following on 09/04/2006 02:53:
> Oli Filth wrote:
>> Jerry Stuckle said the following on 08/04/2006 21:51:
>>
>>> Oli Filth wrote:
>>>
>>>> function getWithDefault(&$array, $key, $default = NULL)
>>>> {
>>>> return (isset($array[$key])) ? $array[$key] : $default;
>>>> }
>>>>
>>>>
>>>
>>> And if $array is empty you get a warning.
>>>
>>
>> You do? I don't. Nor can I see any reason why one should get a
>> warning. What version of PHP are you running?
>>
>
> Try turning on all warnings.


I have error level set to E_ALL | E_STRICT. The following code executes
fine:
<?php

function getValueWithDefault(&$array, $key, $default = NULL)
{
return (isset($array[$key])) ? $array[$key] : $default;
}

$var = array();
echo getValueWithDefault($var, "Roger", "Dodger") . "\n";

?>

I see no reason why an error/warning should get thrown. isset() simply
looks for an element with the specified key name in the associative
array. In an empty array, the key doesn't exist, so isset() returns false.

--
Oli

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