Posted by hph on 04/27/06 05:44

In article <124u2qjs1abpr56@corp.supernews.com>,
gordonb.787qs@burditt.org (Gordon Burditt) wrote:

>
> SELECT DATE_FORMAT(stamp, '%m/%d/%y'), ...
> if you absolutely insist on writing non-Y2K-compliant code.
>
> Gordon L. Burditt


Thanks.

$last_donation=mysql_query("SELECT DATE_FORMAT($year_data[2],
'%j/%n/%Y'");

gave me what I wanted. $last_donation was a variable that I later
echoed, and year_data was a result array into which I'd fetched data,
including a TIMESTAMP data field.

I'm all for Y2K compliance (I won't, however, be around when Y10K
becomes an issue...), but in this case, I'm simply displaying a date in
a format that, I think, seems to appeal to the majority of people in the
US who think of dates as just dates and not data.

Thanks for your patience in answering my trivial questions.

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