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Posted by Kimmo Laine on 05/18/06 11:42
"Alan Little" <alan@n-o-s-p-a-m-phorm.com> wrote in message
news:Xns97C6A5C373D05alanphormcom@216.196.97.131...
> Carved in mystic runes upon the very living rock, the last words of Rik
> of comp.lang.php make plain:
>
>> Alan Little wrote:
>>> Carved in mystic runes upon the very living rock, the last words of
>>> Ambush Commander of comp.lang.php make plain:
>>>
>>>> It looks like in this particular case, $this->$x should be
>>>> sufficient.
>>>
>>> Thanks, but no.
>>>
>>>> Otherwise, you may have to split up x into $x_object and $x_name
>>>> (exploding by -> should be sufficient) and calling
>>>> $x_object->$x_name. What you currently have, however, cannot be
>>>> done.
>>>
>>> I'm not sure what you mean.
>>> What I'm trying to do is parse variables
>>> out of a string and substitute them with the value. $x (in this
>>> example) would hold the variable name extracted from the string. I'm
>>> trying to figure out how to get to the value of that variable, from
>>> there.
>>
>> That is exactly what it does.
>> $x = 'string'
>>
>> $$x = $this->$x;
>> equals:
>> $string = $this->string;
>>
>> $x is the variable name, $variable_name holds the value......
>>
>> I don't get the problem?
>>
>> What is the exact reason you're trying to accomplish? Maybe if you
>> elaborate some more, we get the picture. Why is it this doesn't
>> suffice?
>
> For example:
>
> $this->animal = 'lamb';
> $this->string = 'Mary had a little {{animal}}';
>
> The goal is to extract 'animal' from the string (no problem), convert it
> to 'lamb' and replace it in the string (again, no problem). The question
> is, if I have 'animal', how do I get 'lamb'? In global space, I would
> simply have 'animal' in a variable, and use $$var to get 'lamb'.
>
So again, wouldn't this work:
$var = 'animal';
$this->$var; //this is translated to $this->animal, which in turn gives you
'lamb' .
--
"ohjelmoija on organismi joka muuttaa kofeiinia koodiksi" -lpk
spam@outolempi.net | Gedoon-S @ IRCnet | rot13(xvzzb@bhgbyrzcv.arg)
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