Posted by julianmlp on 05/31/06 21:38

btw, and sorry for the off topic.

Do you know any site which explains why:

d/dx[0] {lim x-->oo (1+1/x)^x} ^ x = 1

I mean, what is the relationship between the limit (1 + 1/x)^x and the
base of the exponential function A <==> d/dx[0]A^x = 1 (of course, A
has to be "2.7182....")

Again, sorry for the off topic

regards - julian

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