Posted by Jerry Stuckle on 07/15/06 03:21

news@smutchin.co.uk wrote:
> Hi all, hope you can help me.
>
> I have recently set up a mysql database of local pubs, with a web form
> to add new listings (using PHP to generate an INSERT query).
>
> I've just been doing a bit of data entry, adding a bunch of new pubs,
> and all was going swimmingly. But suddenly it has stopped working - now
> when I try to add a new pub I get an error message "call to undefined
> function". I have not altered the script in any way since the last
> successful addition was made.
>

What function is undefined?

> I ran a SELECT * query on the pubs table to proofread the entries, but
> couldn't spot any glaring errors. Then I ran a SELECT COUNT(*) on the
> table. The result was 100, ie there were rows numbered 0-99.
>
> I'm wondering if there could be a problem with handling three-figure
> row numbers. It sounds highly unlikely (I've checked the documentation
> so I know the table [MyISAM] is supposed to be able to handle many more
> rows than that).
>

Shouldn't be any PHP problem. If you suspect a MySQL problem try
comp.databases.mysql.

> Maybe it's a restriction imposed by my webhost? (Supanames.co.uk) This
> also sounds unlikely.
>

Did you ask them?

> But in any case, I'm completely baffled. Can anyone suggest any
> possibilities?
>

Sorry, my crystal ball is in the shop and you didn't give enough
information to even know where to start!

> (Btw, I don't know which version of PHP Supanames has installed.)
>

Did you try phpinfo()?

> cheers,
>
> David
>


--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
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