Posted by Alvaro G. Vicario on 08/17/06 21:50

*** lawrence k escribió/wrote (17 Aug 2006 12:48:28 -0700):
> if (is_resource($this->datastoreResultsPointer)) {
> mysql_free_result($this->datastoreResultsPointer);
> mysql_close();
> }
[...]
> Warning: mysql_free_result(): 286 is not a valid MySQL result resource
> in
> /home/httpd/vhosts/monkeyclaus.org/httpdocs/media/audio/pdsIncludes/McDatastoreResultsMySql.php
> on line 89

According to PHP manual, mysql_free_result()'s argument "comes from a call
to mysql_query()." So if you give it, let's say, a resource generated by
fopen(), it will pass the is_resource() check and then fail at
mysql_free_result().

You can try with get_resource_type() or just ignore the error:

@mysql_free_result(........);



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