|
|
Posted by Andrew Poelstra on 08/18/06 04:41
"vetchling" <vetchling@gmail.com> writes:
> Hi, I'm pretty new to php but I've been working on a site and have a
> problem I can't fix, though it's probably pretty simple.
>
> Basically I have an index.php file that includes a header.php file. I
> attempt to pass a variable to it as follows:
> <?include("header.php?page=Home");?>
>
> Then the header.php file contains this code:
> <?php
> $page = $_GET['page'];
> ?>
> <html><head><title><?$page?></title>
>
> I want $page to contain the string "Home" of course, but it ends up
> being nothing but an empty string.
>
> Thanks in advance for your help.
You can't add ?args to an include; PHP doesn't evalutate that when
including files. (In fact, it usually never evaluates URL arguments:
that's the HTTP daemon's job.) It merely copies the contents of
header.php directly into your document (or parses equivilantly).
To do this, you need to do:
#In mypage.php you need to access $mypage_page directly.
mypage_page = "Home";
include ("mypage.php");
I've prefixed the variable $page to avoid naming conflicts.
--
Andrew Poelstra <http://www.wpsoftware.net/projects>
To reach me by email, use `apoelstra' at the above domain.
"Do BOTH ends of the cable need to be plugged in?" -Anon.
[Back to original message]
|