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Posted by Ninad on 08/21/06 08:55
Hi Petr
what i want to say in my code is don't put mysql_fetch_array()
funcstion in while loop condition put it inside the loop your problem
will be solved
Thanks
Ninad
Petr Vileta wrote:
> "Rik" <luiheidsgoeroe@hotmail.com> píe v diskusním pøíspìvku
> news:c204d$44e083c0$8259c69c$13766@news1.tudelft.nl...
>
> > Judging by your output:
> >>
> >> Rows=3
> >> 1
> >> 2
> >> 3
> >> Warning: mysql_fetch_array(): 5 is not a valid MySQL result resource
> >> in F:\webpub\php\test.php on line ...
> >>
> >
> > Do the 1\n2\n3 mean these rows are shown?
>
> Yes
>
> > It would seem a _second_ fetch is performed on the result that we're
> > not aware of.
>
> Hmm, I do to study my code :-) This could be the reason.
>
> > Could you show us the entire relevant code?
> No. The code is not top-secret but is too big and if I delete some parts it
> could be not runable.
>
> --
>
> Petr Vileta, Czech republic
> (My server rejects all messages from Yahoo and Hotmail. Send me your mail
> from another non-spammer site please.)
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