Posted by Chuck Anderson on 06/09/05 22:29

Jamie Meyers wrote:

>"Chuck Anderson" <websiteaddress@seemy.sig> wrote in message
>news:houdnQf0jJq5CzrfRVn-hw@comcast.com...
>
>
>>I have a function with 7 inputs. The last three have default values.
>>
>>I want to call that function specifying the first four, skip two and then
>>specify the last.
>>
>>I thought I could write this as :
>>
>>$retval = myfunction(arg1, arg2, arg3, arg4,,,arg7);
>>
>>
>
>if you wrote myfunction, then declare it like this
>
>
I did write it.

>function myfunction(arg1, arg2, arg3, arg4, arg5="", arg6="", arg7)...
>Where "" should be set to the default values.
>
>
That's actually something the manual says not to do. It says all default
arguments should be on the right and then has an example showing why it
won't work the other way.

My arg 7 has a default value, though, so you're structure is how it
already exists.

>
>
>>... but Php does not seem to want to let me do this. I get a parse error
>>until I supply values for the 5th and 6th arguments.
>>
>>My question is simply this; is skipping arguments like that not allowed in
>>Php?
>>
>>
>>

--
*****************************
Chuck Anderson • Boulder, CO
http://www.CycleTourist.com
Integrity is obvious.
The lack of it is common.
*****************************

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