Posted by Joshie Surber on 09/01/06 21:11

Have you tried forcing your INT into a STRING, or making sure it is a
string? If it is being treated as an INT padding is automatically
disregarded.
comp.lang.php wrote:
> Could someone please spot-check this function and tell me why it never,
> ever, pads an integer with a leading zero when I want it to?
>
> This function fails in PHP 4.3.8, 4.4.1 and 4.3.9
>
> Thanx
> Phil
>
> [PHP]
> f (!function_exists('pad')) {
> /**
> * Pad a string. Use str_pad() as default unless the input string
> value is larger than the amount of padding to take place due to
> str_pad() rules (PHP needs to update this!!)
> *
> * @access public
> * @param mixed $input (reference)
> * @param int $offset Number of times to repeat padding character
> * @param char $padChar Character to pad with
> * @param int $padConstant (optional) PAD_CONSTANT constant value
> (e.g. STR_PAD_LEFT, STR_PAD_RIGHT, etc.)
> * @return mixed $paddedString
> * @link http://us3.php.net/manual/en/function.str-pad.php
> * @see link regarding usage of str_pad() function
> */
> function &pad(&$input, $offset, $padChar, $padConstant =
> STR_PAD_RIGHT) {
> define(PAD_CONSTANT, $padConstant); // MAKE INTO
> CONSTANT FOR NAMING CONVENTION
> if ((int)$offset > 0 && (int)$offset >= strlen($input)) return
> str_pad($input, $offset, $padChar, PAD_CONSTANT); // USE str_pad() BY
> DEFAULT IF RULES APPLY
> if ((int)$offset === 0 || strlen($input) == 0 || !isset($padChar) ||
> strlen($padChar) < 1) return $input; // NOTHING TO PAD
> switch(PAD_CONSTANT) {
> case STR_PAD_LEFT:
> for ($i = 1; $i <= $offset; $i++) $input = "$padChar$input";
> break;
> case STR_PAD_RIGHT:
> for ($i = 1; $i <= $offset; $i++) $input = "$input$padChar";
> break;
> case STR_PAD_BOTH:
> for ($i = 1; $i <= $offset; $i++) $input = "$padChar$input$padChar";
> break;
> default: // DO NOTHING
> break;
> }
> return $input;
> }
> }
> [/PHP]

[Back to original message]