Posted by Chris Hope on 09/15/06 03:40

jds5@xtra.co.nz wrote:

> Hi There,
> I am absolutly stumped by this, any help appreciated.
> Due to factors outside of my control I have a php variable containing
> php code and I dont know how to evaluate it.
>
> I know its stupid, but php calls a database function (which I dont
> have access to) which reads in a template html file and returns it as
> a string. Now If I want the template to be a bit more dynamic and
> contain php I have a problem.
>
> After calling the database function I end up with: (examaple only)
> $var = "<?echo "hello world";?>";
> //$var is now equal to the template file - usually html but attempting
> to add php
>
> now if I echo that out I get:
> <?echo "hello world";?>
> but I want:
> hello world
>
> Can I call another instance of the php interpreter on php variable
> $var?
> Would the eval() function work?
>
> Any way to acheive what I am after?

Use eval() - did you try it? Note that you don't need the <? and ?>
tags. Example:

$var = 'echo "hello world";';
eval($var);

This will display 'hello world' which is what you are wanting.

--
Chris Hope | www.electrictoolbox.com | www.linuxcdmall.com

[Back to original message]