Posted by Johnny on 09/27/06 02:46

"Charles O'Flynn" <charles@matchwalk.com> wrote in message
news:12hj5ffak6bsj3e@corp.supernews.com...
>
> "Charles O'Flynn" <charles@matchwalk.com> wrote in message
> news:12hj1pu2q1pv842@corp.supernews.com...
> |
> | "Johnny" <removethis.huuanito@hotmail.com> wrote in message
> | news:lsfSg.375$UJ2.143@fed1read07...
> ||
> || "Charles O'Flynn" <charles@matchwalk.com> wrote in message
> || news:12hivk1109pj1e0@corp.supernews.com...
> || > As a complete newcomer (2-3 days) to PHP, although not to programming
> in
> || > general, I have 'dived in' to start a small project to read and parse
> an
> || XML
> || > data stream. I have already worked out most of the more specialist
> || aspects
> || > of the job but am now completely stuck on something I would have
> thought
> || > were simplicity itself...
> || > I need to have a large number of global variables visible inside
> || functions -
> || > it's not possible to pass them into the functions themselves, since
> || although
> || > they are user functions, the parameter type/count is fixed. Reading
> | what
> || > information I can find, I was under the impression that variables
> | declared
> || > at the head of the PHP block as 'global' would be visible inside all
> || > functions. My problem is this: yes, it appears I can assign values
to
> || > these global variables inside a function, (I think), but immediately
I
> || exit
> || > the function, the data is lost. At first sight, I could be assigning
> || values
> || > to variables with identical names but local scope within the
functions,
> || but
> || > when I performed an 'explode()' inside a function, assigning the
result
> | to
> || > one of my 'global' variables and then, on exiting the function, tried
> to
> || > 'echo' the result, the result was 'ARRAY' - the original global
> variable
> || had
> || > presumably been converted, since it started life as a scalar.
> || > I don't really want to go to superglobals unless I have to - can
> anybody
> || > please tell me where I'm going so obviously wrong and how I can
correct
> || it?
> || > This is such a basic problem, I can't help thinking everybody must
know
> || the
> || > answer...
> || > Thanks for any help/advice offered.
> || >
> || >
> ||
> || just need to use the global keyword when inside the function, it's
> | explained
> || here:
> || http://us3.php.net/global
> ||
> | Thanks for the quick reply, Johnny, but I've been looking at the page
you
> | refer to all afternoon and it doesn't seem to work for me. For
instance,
> | (and I'm only illustrating the specific problem I seem to have
> hereunder)...
> | ------------------------------------
> | $variable;
> |
> | function printsomething()
> | {
> | global $variable;
> |
> | $variable = 'Test'.<br />;
> | echo $variable;
> | }
> |
> | printsomething();
> | echo $variable;
> | ------------------------------------
> |
> | ...only prints one line of 'Test' - I'd have thought it should print out
> two
> | copies. BTW, I'm running under PHP 4.1.2 (and it's not mine to
> | change/upgrade!)
> | Thanks and regards,
> | Charles
> |
> ********************************************************
> I thought I'd just try out what I wrote above and loaded this up...
>
> <?php
> $loc_place;
>
> function writesomething()
> {
> global $loc_place;
>
> $loc_place = 'This is a test';
> echo $loc_place.'<br />';
> }
>
> echo $loc_place.' again<br />';
> writesomething();
> ?>
>
> As I wrote earlier, I get no sign of any output from outside the function,
> only inside...
>
> This is a test
>
> Surely this cannot be right?
>
>
that's because when you do the line
echo $loc_place.' again<br />';

$loc_place has not been assigned a value until the next line when you call
writesomething. Up until then you have defined the function but not run it
so that var is undefined.

try switching the last two lines...

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