Reply to Re: Error - Cannot pass paramter --> Failed to open stream

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Posted by One on 10/01/06 01:46

Jerry Stuckle wrote:
> Colin McKinnon wrote:
> > One wrote:
> >
> >
> >>Andy Hassall wrote:
> >>
> >>> You can't do that. "?" is for URLs, but you're specifying a filename.
> >>> With the
> >>>"?", you're specifying a filename that doesn't exist.
> >>
> >>ah ha. I know - In the past I have passed it as a parameter like this :
> >>include "http://www.www.com/file.php?menu=david"
> >>This has worked.
> >
> >
> > Yes, but its very dangerous unless you really, really know what you're
> > doing.
> >
> >>> If you want to pass variables into the include file, just set them
> >>> before you
> >>>do the include, they'll be visible in the include file. (Or pass them as
> >>>parameters to whatever functions you define in the include file).
> >>
> >>You mean like this ?
> >>
> >><?php
> >>echo "<form><input type="hidden" name=menuid" value="david"></form>";
> >>include file.php
> >>?>
> >>
> >
> > No - like
> >
> > $GLOBALS['menuid']='david';
> > include ('file.php');
> >
> > C.
> >
>
> You don't even need to use globals.
>
> Just
>
> $menuid = 'david';
>
> and in the include file you can use
>
> if ($menuid == 'david') ...
>

Yeah!!

Big thanks to Jerry and Colin. I have successfully impltmented your
solution.

BTW - what is the risk passing the variable to the file via and httP
request ?
The include file has nothing to execute.

thanks again!

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