Posted by Robin on 10/10/06 18:28

Bit Byte wrote:
> 1). Is the function signature correct (valid syntax?)

Depends on your PHP-Version, i.e.:

PHP 4:
function foo(&$arr){}

PHP 4 knows nothing about visibilty and always passes by value, hence
the '&' to signal a pass-by-reference. Nice text about using objects
and references in PHP 4:
http://www.obdev.at/developers/articles/00002.html

PHP 5:
public function foo(array $arr){}

PHP 5 always passes by reference, so no '&' is needed.

Cheers
Robin

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