Reply to Re: PHP 5 / MySQL 5 subquery problem

Your name:

Reply:


Posted by Diogenes on 10/11/06 15:54

Captain Paralytic wrote:
> Diogenes wrote:
>>
>>SELECT pkey, Name FROM tracks WHERE artist="Rolling Stones"
>>AND pkey NOT IN (SELECT Song FROM requests WHERE client="jim")
>>
>
>
> It is almost always more efficient to use the LEFT JOIN alternative for
> this task
>

I'm a little naive on SQL. Could you redo the above SELECT
statement with your suggested alternative? Then I'll try it
in PHP.

Cheers
Jim

[Back to original message]


Удаленная работа для программистов  •  Как заработать на Google AdSense  •  England, UK  •  статьи на английском  •  PHP MySQL CMS Apache Oscommerce  •  Online Business Knowledge Base  •  DVD MP3 AVI MP4 players codecs conversion help
Home  •  Search  •  Site Map  •  Set as Homepage  •  Add to Favourites

Copyright © 2005-2006 Powered by Custom PHP Programming

Сайт изготовлен в Студии Валентина Петручека
изготовление и поддержка веб-сайтов, разработка программного обеспечения, поисковая оптимизация