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Posted by Kimmo Laine on 10/18/06 08:03
<mosesdinakaran@gmail.com> wrote in message
news:1161156743.321309.53790@k70g2000cwa.googlegroups.com...
> Hi everybody,
>
> Today I faced a problem where I am very confused and I could not
> solve it and I am posting here....
>
> My question is
> Is is possible to return a value to a particular function
>
> The question may be silly or even meaning less but
> please............
>
> Below I have give a detailed description on why this question
> appears to me.
>
> Consider the following Code.
>
> function one()
> {
> $ret_val = three();
> echo "<br>RetVal:=".$ret_val;
> }
> function two($a,$b)
> {
> echo "<br>I am In function ".__FUNCTION__."()";
> if($a==$b)
> return true;
> else
> return false;
> }
> function three()
> {
> $array_one= array(1,2,3,4,5);
> $array_two= array(1,2,3,4,5);
> $a = array_rand($array_one,1);
> $b = array_rand($array_two,1);
> if(two($a,$b))
> {
> $ret_val = "$a and $b are equal";
> echo "<br><br>I am In function ".__FUNCTION__."() and the
> Val is $ret_val<br>";
> return $ret_val;
> }
> else
> {
> three();
NOTE: This should be: return three();
> }
>
> }
> one();
>
> Whats happpening here is.
>
> 1) I have three functions named one() two() and three();
> 2) From the first function one() I am calling function three()
> 3) In function three I have two arrays named $array_one and
> $array_two
> 4) Then I am getting a random value from this two arrays as $a,$b
> 5) Then the function two is called to check weathe this two
> random value is equal or not if the values are equal it returns true
> else false
> 6) Function three is called recursly till the random value $a
> and $b are equal. If it is equal I need to return the two values to
> function one()
> 7) At one time $a and $b will be equal at this moment I return a
> variable $ret_val from function three() to function one()
> 8) So In function one I can get the $ret_val
>
> But I could not get the value $ret_val in function one()
> I dont know why........
>
> I should return the value $ret_val from function three() to
> function one() But it is not happening I dont know weather the value
> has been returned to function three() or to function two()
When you call three() recursively, you're not returning the value there.
When you call two in the other branch, you are returning the value there,
but it's lost since you've broken the chain of returns when calling three.
It goes something like this:
one() calls three(), prints what three() returns
three() calls three(), returns nothing
three() calls three(), returns nothing
three() calls three(), returns nothing
three() calls three(), returns nothing
.... at some point random matches and...
three() calls two(), returns $retval
It should be
one() calls three, prints what three() returns
three() calls three(), returns what three() returns
three() calls three(), returns what three() returns
....
three() calls two(), returns $retval
so that $retval can make it back to one(). Kudos on using recursion, you
just missed a tiny little detail... Always return a recursive funtion call.
--
"Ohjelmoija on organismi joka muuttaa kofeiinia koodiksi" - lpk
http://outolempi.net/ahdistus/ - Satunnaisesti pδivittyvδ nettisarjis
spam@outolempi.net | rot13(xvzzb@bhgbyrzcv.arg)
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