Posted by linda on 11/18/06 21:31

"linda" <n0spamF0rme@tiscali.co.uk> wrote in message
news:455f77d1_2@mk-nntp-2.news.uk.tiscali.com...
>
> "MS" <MS@nospam.com> wrote in message
> news:X6SdnSEfJNJKxcLYnZ2dnUVZ8tKdnZ2d@bt.com...
>> >
>>> for ($year=2006; $year>=1945; $year--) {
>>>
>>
>> The above will work fine as you have found, but if you hard code the
>> Years
>> then next year, and subsequent years, you will need to change your code
>> to
>> allow for year 2007, 2008 etc...
>>
>> You may find this helpful
>>
>> for ($year=date('Y'); $year>=(date('Y')-100); $year--) {
>>
>> this will list the previous 100 years !!
>>
>> MS
>> ----
>> Join MyClubWeb.co.uk - The Home of Club Websites and Medium to Small
>> Businesses.
>>
>>
>
> Hi MS,
>
> You must have been looking over my sholder lol... i did this very same
> thing this after noon like this:
>
> //Make the years
> $thisyear = date('Y');
>
> echo '<select name="year">';
> for ($year=$thisyear; $year>=1945; $year--) {
> echo "<option value=\"$year\">$year</option>\n";
> }
> echo '</select>';
>
> Will you please stay out of my bedroom ;-)
>
> Best wishes,
> Linda
>
Your hundred year difference is a good idea though, and it's a lot more
compact, so thank you I've altered my code to the way you have shown thank
you.

Best wishes,
Linda

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