Posted by John Nichel on 01/06/05 21:20

Wil Hitchman wrote:
> I get the following error
>
> Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /home/wilmail/public_html/elblog.php on line 7
> &n=& //error ends here
>
> with the following bit of code
>
> $qResult = mysql_query ("SELECT * FROM blog_entries ORDER BY id DESC");
>
> $nRows = mysql_num_rows($qResult);
> $rString ="&n=".$nRows;
>
> If I am just naming a variable how is the argument not valid?
>
> Thanks,
>
> Wil

Echo out mysql_error() after you execute mysql_query()

--
John C. Nichel
ÜberGeek
KegWorks.com
716.856.9675
john@kegworks.com

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