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Posted by Kimmo Laine on 12/05/06 09:04
"Sonnich" <sonnich.jensen@elektrobit.com> wrote in message
news:1165309352.222966.35270@16g2000cwy.googlegroups.com...
>
> Kimmo Laine wrote:
>> "Sonnich" <sonnich.jensen@elektrobit.com> wrote in message
>> news:1165307408.725039.279250@f1g2000cwa.googlegroups.com...
>> > I'd like to read out a date from the a DB, but as time var. By default
>> > I seem to get it as a string.
>> >
>> > E.g.
>> > while(odbc_fetch_row($result))
>> > {
>> > $tt= odbc_result($result,2);
>> > echo date("d.m.Y", $tt).", ".odbc_result($result,6) . " <br>";
>>
>>
>> What kind of a string it is? If it's just a regular Y-m-d string, then
>> the
>> easiest would be first converting it to unix timestamp and then passing
>> that
>> to date:
>> date("d.m.Y", strtotime($tt));
>>
>> strtotime parses the formatted date string and converts it to integer.
>
> Server default format, I guess....
> 2006-12-05 00:00:00
Then strtotime is your friend. Just pass the timestring the server gives to
strtotime and use the timestamp it returns.
--
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http://outolempi.net/ahdistus/ - Satunnaisesti pδivittyvδ nettisarjis
spam@outolempi.net | rot13(xvzzb@bhgbyrzcv.arg)
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